Business Statistics Solved Paper FBISE 2017 2nd Annual ICOM II, MCQS, Short Questions, Extensive Questions

Business Statistics Solved Paper FBISE 2017 2nd Annual ICOM II, MCQS, Short Questions, Extensive Questions

In this blog post, I am going to discuss the paper of Business Statistics Solved Paper FBISE 2017 2nd Annual ICOM II, MCQS, Short Questions, Extensive Questions topics included are Introduction to StatisticsAverages, Index Numbers, Probability. Solved paper of Business Statistics Paper 2012 & solved paper of Business Statistics 2013Business Statistics 2015Business Statistics 2016Business Statistics 2016 Supplementary, Business Statistics 2017 are already published on the website. Stay Connected for other boards solutions such as BISELHRBISERWP etc.

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Business Statistics Solved Paper FBISE 2017 2nd Annual ICOM II, MCQS, Short Questions, Extensive Questions

MCQS

Q.1 Choose the correct answer A / B / C / D by filling the relevant bubble for each question on the OMR Answer Sheet according to the instructions given there. Each part carries one mark.

(i)The data, which have not undergone any statistical treatment, are:
 A. Primary DataB. Secondary DataC. Discrete dataD. Continuous data 
      
(ii)In the plural sense, statistics means:
 A. MethodB. Numerical dataC. Sample dataD. Population data 
      
(iii)The graph of time series is:
 A. Pie-ChartB. OgiveC. HistogramD. Historigram 
      
(iv)Relative frequency can never be:
 A. Less than oneB. More than oneC. Equal to oneD. Equal to two 
      
(v)The median of 3,4, 5, 6, 9, 10, 12 is:
 A.B.C. D. 
      
(vi)The most frequent value in the data is:
 A. MeanB. MedianC. ModeD. Standard Devitaion 
      
(vii)In fixed base method, the base period should be:
 A. Far awayB. NormalC. AbnormalD. Unreliable 
      
(viii)The weights in a price index are:
 A. Average of pricesB. Percentage of pricesC. Not importantD. Quantities 
      
(ix)When two coins are tossed, the possible outcomes are:
 A. 1B. 2C. 4D. 36 
      
(x)If A and B are two independent events then:
 A. P(A) = P(B)B. P(A∩B) = P(A)P(B)C. P(A∩B) ≠ P(A)P(B)D. P(A/B) = P(B) 
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Short Questions

Q.2 Attempt any eight parts. The answer to each part should not exceed 3 to 4 lines. (8 x 3 = 24)

(i) What is Statistics?

Answer:

Statistics is a branch of applied mathematics. Statistics is a science of average and probability in which it delas with data into four different parts such as:

  1. Collection of data
  2. Organization of data
  3. Analysis or interpretation of data
  4. Presentation of data

(ii) Name the methods of collecting primary data.

Answer:

  1. Direct Questionnaire
  2. Through SMS
  3. Through Telephone
  4. Through Social Media Platforms
  5. Through Poll

(iii) What is Histogram?

Answer:

Histogram is a graphical representation of a frequency or probability distribution of the data. In Histogram, we take range of values on x-axis whereas frequency of specific values is taken on y-axis.

(iv) Differentiate between qualitative and quantitative data.

Answer:

Qualitative data is a data in which, we present the data in terms of quality or attribute such as grades, Color of eyes etc.

Quantitative data is a data in which we present the data in terms of quantity, numeric or digits such as, income, saving, consumption etc.

(v) Monthly earnings of 10 employees are: 100, 120, 130, 110, 109, 101, 150, 190, 170, and 200. Calculate average earning of employees.

Solution:

Employees (X)100120130110109101150190170200∑X =1380

    \[ \overline X=\frac{\sum X}n=\frac{1380}{10}=138  \]

(vi) For a certain distribution, the value of mean is 15 and median is 20. What will be the value of mode?

Solution:

Mode = 3Median – 2Mean

Mode = 3(20) – 2(15)

Mode = 60 – 30

Mode = 30

(vii) If  and Y = 3X + 9, then find Y̅.

Solution:

Here, we can use the equation of the calculation of an intercept:

    \[ a=\overline Y\;-b\overline X \]

where b is a coefficient and that is 3, a is a constant and that is 9. Put the values in the equation, we get:

    \[ a=\overline Y\;-b\overline X \]

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    \[ 9=\overline Y\;-\;(3)\;(15) \]

    \[ \overline Y\;=9+45=54 \]

(viii) Define an index number.

Answer:

Index number is a statistical measure that calculates or measure the change in price or quantity with respect to time. It is a measure for recording inflation or deflation in the economy. It is barometer of economics.

(ix) Construct chain base index number for the following data:

Year:194119421943194419451946
Price:122124118125128135

Solution:

YearPriceLink RelativeChain Index
1941122100100
1942124

    \[ \frac{\mathbf{124}}{\mathbf{122}}\mathbf{\times 100 = 101.63}\  \]

    \[ \frac{\mathbf{100 \times 101.63}}{\mathbf{100}}\mathbf{= 101.63}\  \]

1943118

    \[ \frac{\mathbf{1}\mathbf{18}}{\mathbf{12}\mathbf{4}}\mathbf{\times 100 =}\mathbf{95.16}\  \]

    \[  \frac{\mathbf{101.63 \times}\mathbf{95.16}}{\mathbf{100}}\mathbf{=}\mathbf{96.71}\ \]

1944125

    \[ \frac{\mathbf{12}\mathbf{5}}{\mathbf{1}\mathbf{18}}\mathbf{\times 100 = 10}\mathbf{5.93}\  \]

    \[ \frac{\mathbf{96.71}\mathbf{\times}\mathbf{105.93\ }}{\mathbf{100}}\mathbf{= 102.44}\ \]

1945128

    \[ \frac{\mathbf{12}\mathbf{8}}{\mathbf{12}\mathbf{5}}\mathbf{\times 100 = 10}\mathbf{2.4}\  \]

    \[  \frac{\mathbf{102.44}\mathbf{\times 10}\mathbf{2.4}\mathbf{\ }}{\mathbf{100}}\mathbf{= 10}\mathbf{4.89}\ \]

1946135

    \[ \frac{\mathbf{1}\mathbf{35}}{\mathbf{12}\mathbf{8}}\mathbf{\times 100 = 10}\mathbf{5.46}\ \]

    \[  \frac{\mathbf{104.89}\mathbf{\times 105.}\mathbf{46}\mathbf{\ }}{\mathbf{100}}\mathbf{= 1}\mathbf{10.61}\ \]

(x) State addition law of probability for mutually exclusive events.

Answer:

P(A or B) = P(A) + P(B)

(xi) What are independent events?

Answer:

If two or more than two events have nothing common between them, then the events are called independent events. For example:

A: {1, 3, 5, 7, 9} and event B: {2, 4, 6, 8, 10} have nothing common between them so these are independent events.

Extensive Questions

SECTION C (Marks: 16)

Note: Attempt any TWO questions. All questions carry equal marks.           (2×8=16)

Q.3 Calculate median and mode of the following distribution.

Weight0—7 7—1414—2121—2828—3535—42 42—49
Frequency19253672514328

Solution:

WeightFrequencyXC.F
0—7 193.519
7—142510.544
14—213617.580
21—287224.5152
28—355131.5203
35—42 4338.5246
42—492845.5274
∑f = n = 274

    \[ \left( \mathbf{i} \right)\mathbf{\ Median = L +}\frac{\mathbf{h}}{\mathbf{f}}\mathbf{(}\frac{\mathbf{n}}{\mathbf{2}}\mathbf{- \ C)}\  \]

Model Class = n/2 = 274/2 = 137 falls in C.F of 152 so data is:

L = 21, h = 7, f = 72, n/2 =274/2 = 137 & C = 80

    \[ \mathbf{Median = L +}\frac{\mathbf{h}}{\mathbf{f}}\left( \frac{\mathbf{n}}{\mathbf{2}}\mathbf{- \ C} \right)\  \]

    \[ \mathbf{Median = 21 +}\frac{\mathbf{7}}{\mathbf{72}}\left( \mathbf{137 - \ 80} \right)\mathbf{\ }\mathbf{\ }\  \]

    \[ \mathbf{Median = 26.54}\ \]

    \[ \left( \mathbf{ii} \right)\mathbf{\ Mode = L +}\frac{\mathbf{fm - f}\mathbf{1}}{\left( \mathbf{fm - f}\mathbf{1} \right)\mathbf{+ \ (fm - f}\mathbf{2)}}\mathbf{x\ h}\  \]

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Model Class: Maximum frequency is 72 so data for model class is:

L = 21, fm = 72, f1 = 36, f2 = 51 & h = 7

    \[ \mathbf{Mode = 21 +}\frac{\mathbf{72 - 36}}{\left( \mathbf{72 - 36} \right)\mathbf{+ \ (72 - 51)}}\mathbf{\times \ 7}\  \]

    \[ \mathbf{Mode = \ 21 +}\frac{\mathbf{36}}{\mathbf{57}}\mathbf{\times \ 7\ = 25.42}\  \]

Q.4 Show with the help of following data that Fisher’s index is Geometric mean of Laspeyre’s and Paasche’s index.

CommodityBase YearCurrent Year
Price (Po)Quantity(qo)Price (p1)Quantity(q1)
A12501055
B61004120
C555360
D1030535

Solution:

CommodityBase YearCurrent YearBase Year
Price (po)Quantity(qo)Price (p1)Quantity(q1)poqop1qop1q1poq1
A12501055600500550660
B61004120600400480720
C555360275115180300
D1030535300150175350
Sum1775116513852030
 ∑poqo =∑p1qo =∑p1q1 =∑poq1 =

    \[ \mathbf{Laspeyre's}\mathbf{\ Index}\mathbf{=}\frac{\mathbf{\sum}\mathbf{p1qo}}{\mathbf{\sum}\mathbf{poqo}}\mathbf{\times}\mathbf{\ 100}\  \]

    \[ \mathbf{Laspeyre's}\mathbf{\ Index}\mathbf{=}\frac{\mathbf{1165}}{\mathbf{1775}}\mathbf{\times \ 100}\mathbf{= 65.63}\  \]

    \[ \mathbf{Paasche's\ index}\mathbf{=}\frac{\mathbf{\sum}\mathbf{p1q1}}{\mathbf{\sum}\mathbf{poq1}}\mathbf{\times}\mathbf{\ 100}\  \]

    \[  \mathbf{Paasche's\ index}\mathbf{=}\frac{\mathbf{1385}}{\mathbf{2030}}\mathbf{\times \ 100 = 68.22}\ \]

    \[ \mathbf{Fishe}\mathbf{r}^{\mathbf{'}}\mathbf{s\ Ideal\ Index\ =}\sqrt{\mathbf{L \times P}}\  \]

    \[ \mathbf{Fishe}\mathbf{r}^{\mathbf{'}}\mathbf{s\ Ideal\ Index\ =}\sqrt{\mathbf{65.63\ \times \ 68.22}}\ \]

    \[ \mathbf{Fishe}\mathbf{r}^{\mathbf{'}}\mathbf{s\ Ideal\ Index\ = 66.91}\  \]

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Q.5 Show that in a single throw with two dice, the chance of throwing more than 7 is equal to that of throwing less than 7 and hence find probability of throwing exactly 7.

Solution

    \[ Sample\;Space\;=\;\begin{pmatrix}N\\C\\n\end{pmatrix}=\begin{pmatrix}6\\C\\2\end{pmatrix}=36 \]

All Possible Outcome

1, 12, 13, 14, 15, 16, 1
1, 22, 23, 24, 25, 26, 2
1, 32, 33, 34, 35, 36, 3
1, 42, 43, 44, 45, 46, 4
1, 52, 53, 54, 55, 56, 5
1, 62, 63, 64, 65, 66, 6

Sum Table

234567
345678
456789
5678910
67891011
789101112

Events

    \[  \left( \mathbf{i} \right)\mathbf{\ More\ than\ 7\ \eta}\left( \mathbf{A} \right)\mathbf{=}\mathbf{15}\ \]

    \[ \left( \mathbf{ii} \right)\mathbf{\ Less\ than\ 7\ \eta}\left( \mathbf{B} \right)\mathbf{=}\mathbf{15}\  \]

    \[ \left( \mathbf{iii} \right)\mathbf{\ Exactly\ 7\ \eta}\left( \mathbf{C} \right)\mathbf{=}\mathbf{6}\  \]

Probabilities

    \[ \left( \mathbf{i} \right)\mathbf{P}\left( \mathbf{A} \right)\mathbf{=}\frac{\mathbf{\eta(A)}}{\mathbf{\eta(S)}}\mathbf{=}\frac{\mathbf{15}}{\mathbf{36}}\mathbf{= 0.417}\  \]

    \[  \left( \mathbf{ii} \right)\mathbf{P}\left( \mathbf{B} \right)\mathbf{=}\frac{\mathbf{\eta(B)}}{\mathbf{\eta(S)}}\mathbf{=}\frac{\mathbf{15}}{\mathbf{36}}\mathbf{= 0.417}\ \]

    \[ \left( \mathbf{iii} \right)\mathbf{P}\left( \mathbf{C} \right)\mathbf{=}\frac{\mathbf{\eta(C)}}{\mathbf{\eta(S)}}\mathbf{=}\frac{\mathbf{6}}{\mathbf{36}}\mathbf{= 0.167}\  \]

Probability of more than 7 is equals to the probability of less than 7 and probability of exactly 7 is 0.167

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Business Statistics Solved Paper FBISE 2012 ICOM II, MCQS, Short Questions, Extensive Questions

Business Statistics Solved Paper FBISE 2013 ICOM II, MCQS, Short Questions, Extensive Questions

Business Statistics Solved Paper FBISE 2015 ICOM II, MCQS, Short Questions, Extensive Questions

Business Statistics Solved Paper FBISE 2016 ICOM II, MCQS, Short Questions, Extensive Questions

Business Statistics Solved Paper FBISE 2016 2nd Annual ICOM II, MCQS, Short Questions, Extensive Questions

Business Statistics Solved Paper FBISE 2017 ICOM II, MCQS, Short Questions, Extensive Questions

Consignment Account, Consignor or principal, Consignee or agent, Complete Analysis with Journal Entries, Theoretical Aspect, MCQ’s and Practical Examples

Depreciation, Reasons of Depreciation, Methods of Depreciation, Straight Line/ Original Cost/Fixed Instalment Method, Diminishing/Declining/Reducing Balance Method.

Introduction to Statistics Basic Important Concepts

Measures of Central Tendency, Arithmetic Mean, Median, Mode, Harmonic, Geometric Mean

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